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Free PDF Quiz 2025 1z1-071: Authoritative Oracle Database SQL Reliable Test Syllabus
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Oracle 1z1-071 Exam covers a wide range of topics, including data retrieval using SELECT statements, data manipulation using DML statements, and database schema design. 1z1-071 exam also covers advanced SQL concepts such as subqueries, joins, and set operators. The test is designed to measure an individual's ability to write effective SQL queries and to ensure they understand the underlying concepts.
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Oracle Database SQL Sample Questions (Q243-Q248):
NEW QUESTION # 243
View the Exhibit and examine the structure of ORDERS and ORDER_ITEMS tables.
ORDER_ID is the primary key in the ORDERS table. It is also the foreign key in the ORDER_ITEMS table wherein it is created with the ON DELETE CASCADE option.
Which DELETE statement would execute successfully?
- A. DELETE order_idFROM ordersWHERE order_total < 1000;
- B. DELETE ordersWHERE order_total < 1000;
- C. DELETEFROM ordersWHERE (SELECT order_idFROM order_items);
- D. DELETE orders o, order_items IWHERE o.order_id = i.order_id;
Answer: C
NEW QUESTION # 244
View the Exhibit and examine the structure in the EMPLOYEES tables.
Evaluate the following SQL statement:
SELECT employee_id, department_id
FROM employees
WHERE department_id= 50 ORDER BY department_id
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=90
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=10;
What would be the outcome of the above SQL statement?
- A. The statement would execute successfully but it will ignore the ORDER BY clause and display the rows in random order.
- B. The statement would not execute because the positional notation instead of the column name should be used with the ORDER BY clause.
- C. The statement would not execute because the ORDER BY clause should appear only at the end of the SQL statement, that is, in the last SELECT statement.
- D. The statement would execute successfully and display all the rows in the ascending order of DEPARTMENT_ID.
Answer: C
NEW QUESTION # 245
View the exhibit and examine the ORDERStable.
The ORDERStable contains data and all orders have been assigned a customer ID. Which statement would add a NOTNULLconstraint to the CUSTOMER_IDcolumn?
ALTER TABLE orders
- A. MODIFY customer_id CONSTRAINT orders_cust_nn NOT NULL (customer_id);
ALTER TABLE orders - B. ADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL;
- C. MODIFY CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
ALTER TABLE orders - D. ADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
ALTER TABLE orders
Answer: A
Explanation:
Explanation/Reference:
NEW QUESTION # 246
The following are the steps for a correlated subquery, listed in random order:
* The WHERE clause of the outer query is evaluated.
* The candidate row is fetched from the table specified in the outer query.
* This is repeated for the subsequent rows of the table, till all the rows are processed.
* Rows are returned by the inner query, after being evaluated with the value from the candidate row in the outer query.
Which is the correct sequence in which the Oracle server evaluates a correlated subquery?
- A. 4, 2, 1, 3
- B. 2, 4, 1, 3
- C. 4, 1, 2, 3
- D. 2, 1, 4, 3
Answer: B
Explanation:
Explanation
References:
http://rajanimohanty.blogspot.co.uk/2014/01/correlated-subquery.html
NEW QUESTION # 247
View the exhibit and examine the structure in ORDERS and ORDER_ITEMS tables.
You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATE VIEW statement would create the views successfully?
- A. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;
- B. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;
- C. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date, COUNT (i.line_item_id) ||"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_dateWHITH CHECK OPTION;
- D. CREATE OR REPLACE VIEW ord_vu (order_id, order_date)AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;
Answer: A
NEW QUESTION # 248
......
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